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12 February, 02:37

A rock is thrown horizontally off a cliff with an initial speed of 3 m/s. The initial position of the rock is 10 meters above the ground. How long is the rock in the air?

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  1. 12 February, 04:46
    0
    1.43 s.

    Explanation:

    Using one of the equations of motion,

    S = ut + 1/2gt² ... Equation 1

    Where S = height of the cliff, u = initial velocity, t = time, g = acceleration due to gravity.

    Note: When the rock begins to fall from the maximum height, u = 0 m/s, g = positive

    Given: S = 10 m, u = 0 m/s

    Constant: g = 9.8 m/s²

    Substituting these values into equation,

    10 = 0 (t) + 1/2 (9.8) (t²)

    10 = 0 + 4.9t²

    t² = 10/4.9

    t² = 100/49

    t = √ (100/49)

    t = 10/7

    t = 1.43 s.

    Thus the rock spend 1.43 s in air
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