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31 July, 05:23

In a two-slit setup, each slit is 0.02 mm wide. These apertures are illustrated by plane waves of sodium light (wavelength = 589.6 nm). The resulting fringe pattern consists of 11 narrow fringes that gradually decrease in intensity with distance from the central maximum. Determine the separation between the slits.,

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  1. 31 July, 07:45
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    d = 0.22 mm

    Explanation:

    The phenomenon of interference and diffraction is always present, the latter is the envelope that modulates the process, let's write the equation of each

    Interference d sin θ = m λ

    Diffraction a sin θ = n λ

    Where d is the separation between the slits, a is the width of each, n and m are integers

    In general, the most intense diffraction order is the first, so we can do n = 1, divide the two equations

    d sin θ / a sin θ = m λ / λ

    d / a = m

    They give us the number of interference lines (m = 11), the width of each slit (a = 0.02 mm) and the wavelength (λ = 589.6 nm), let's calculate

    d = a m

    d = 0.02 11

    d = 0.22 mm
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