Ask Question
15 September, 15:35

A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 500 V. The rate at which electrical energy is dissipated in the resistor is 296 W Part A

What is the impedance Z of the circuit?

Express your answer to three significant figures and include the appropriate units.

Part B

What is the amplitude of the voltage across the inductor?

Express your answer to three significant figures and include the appropriate units

Part C

What is the power factor?

Express your answer using three significant figures.

+5
Answers (1)
  1. 15 September, 18:48
    0
    Rate of dissipation of energy at resistor

    = I² R = 296

    current I² = 296/R = 296 / 300

    I = 0.9933 A.

    Impedence Z = V / I = 500 /.9933

    = 503 ohm.

    B) Let it be V

    voltage across resistance = 300 x. 9933 = 298 v

    Now 500² = 298² + V²

    V = 401 v

    C) Power factor = R / Z

    =300 / 503

    = 0.596
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 500 V. The rate at which ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers