A beam of white light goes from air into water at an incident angle of 61.0. At what angles are the red (660 nm) and blue (470 nm) parts of the answer to at least one decimal place.) red 41.07 blue 40.686

41.07 deg

40.686 deg

Explanation:

For Red light:

n₁ = index of refraction of air = 1

i = angle of incidence = 61.0°

n₂ = index of refraction of water = 1.331

r = angle of refraction = ?

Using Snell's law

n₁ Sini = n₂ Sinr

(1) Sin61.0 = (1.331) Sinr

r = 41.07 deg

For Blue light:

n₁ = index of refraction of air = 1

i = angle of incidence = 61.0°

n₂ = index of refraction of water = 1.340

r = angle of refraction = ?

Using Snell's law

n₁ Sini = n₂ Sinr

(1) Sin61.0 = (1.340) Sinr

r = 40.686 deg