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3 February, 11:01

What is the net force on a 7.2-kg car that increases its speed from 8.0 m/s to 14.0 m/s over 5.3 seconds?

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Answers (2)
  1. 3 February, 12:35
    0
    Answer: 8.14 N

    Explanation: To solve for F we use F=ma. First we solve for acceleration a=vf - vi/t

    14m/s-8m/s / 5.3 s = 1.13 m/s²

    Substitute the value to find F.

    F=7.2kg x 1.13 m/s² = 8.14 N
  2. 3 February, 15:00
    0
    8.15

    Explanation:

    From the formula, F = ma we can say:

    F = 7.2 * a

    since a isn't given in the question and f is not also given, we find a.

    so a = change in velocity with time

    i. e a = V-v : t

    therefore, we can say

    14.0-8.0 : 5.3

    that will give us

    6/5.3 = 1.132

    go back to the formula and put in the parameters

    therefore, F = ma gives

    F = 7.2*1.132

    Ans = 8.15N
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