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16 May, 23:53

An engine has a hot-reservoir temperature of 980 K and a cold-reservoir temperature of 570 K. The engine operates at three-fifths maximum efficiency. What is the efficiency of the engine?

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Answers (2)
  1. 17 May, 00:14
    0
    E = 0.251 or 25.1%

    The efficiency of the engine is 0.251 or 25.1%

    Explanation:

    Maximum Efficiency of an engine can be expressed as;

    Em = workdone/heat energy supplied

    Em = 1 - Qc/Qh = 1 - Tc/Th

    Given;

    Tc = cold temperature = 570K

    Th = hot temperature = 980K

    Substituting the values;

    Em = 1 - 570/980

    Em = 0.4184

    But the engine operates at three-fifths the maximum efficiency

    E = 3/5 * Em

    Substituting Em

    E = 3/5 * 0.4184

    E = 0.251 or 25.1%

    The efficiency of the engine is 0.251 or 25.1%
  2. 17 May, 02:17
    0
    efficiency of engine is 0.21

    Explanation:

    given:

    Th=980 K

    Tc=570 K

    since efficiency of engine is given as:

    n=3/5*n_m

    =3/5 (1-Tc/Th)

    =0.21

    efficiency of engine is 0.21
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