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23 March, 17:54

A man pushes an 250-N crate at constant speed a distance of 30.0 m upward along a rough slope that makes an angle of 60° with the horizontal. The work done by the force of gravity is:

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  1. 23 March, 20:19
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    6495.19 Joule

    Explanation:

    F = Weight of the crate = 250 N

    d = Distance the cart is pushed = 30 m

    θ = Angle of inclination = 60°

    The weight of the crate will be resloved into two components

    Fdsinθ and Fdcosθ

    Work done by the force of gravity is

    W = Fdsinθ

    ⇒W = 250*30*sin60

    ⇒W = 6495.19 Joule

    ∴ The work done by the force of gravity is 6495.19 Joule
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