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16 July, 20:59

A hot air balloon is filled with 1.45 * 10 6 L of an ideal gas on a cool morning (11 ∘ C). The air is heated to 109 ∘ C. What is the volume of the air in the balloon after it is heated?

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  1. 17 July, 00:42
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    The volume of air after the balloon is heated = 1.95 * 10⁶ L

    Explanation:

    Charles Law: Charles' law states that the volume of a given mass of gas is directly proportional to the temperature in Kelvin, provided that the pressure remains constant.

    It can be expressed mathematically as,

    V₁/T₁ = V₂/T₂

    Making V₂ The subject of the equation

    V₂ = (V₁/T₁) T₂ ... Equation 1

    Where V₁ = Initial Volume, T₁ = Initial Temperature, V₂ = Final Volume, T₂ = final Temperature

    Given: V₁ = 1.45 * 10⁶ L, T₁ = 11 °C = (11 + 273) K = 284 K, T₂ = 109 °C = (109 + 273) = 382 K.

    Substituting these values into equation 1 above,

    V₂ = (1.45*10⁶) 382/284

    V₂ = 1.95 * 10⁶ L

    Therefore the volume of air after the balloon is heated = 1.95 * 10⁶ L
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