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25 August, 10:28

An archer pulls her bowstring back 0.396 m by exerting a force that increases uniformly from zero to 237 N. (a) What is the equivalent spring constant of the bow? 598.48 Correct: Your answer is correct. N/m (b) How much work does the archer do on the string in drawing the bow?

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  1. 25 August, 12:46
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    (a) The equivalent spring constant is 598.485 N/m

    (b) The work done is 46.926 J

    Explanation:

    From Hooke's law of elasticity

    K (spring constant) = F/e

    F is the range of force exerted = 237 - 0 = 237 N

    e is the extension of bowstring = 0.396 m

    K = F/e = 237/0.396 = 598.485 N/m

    Work done = 1/2 Fe = 1/2 * 237 * 0.396 = 46.926 J
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