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20 May, 03:40

Calculate the average speed of a complete round trip in which the outgoing 300 km is covered at 93 km/h, followed by a 1.0-h lunch break, and the return 300 km is covered at 56 km/h. Express your answer to two significant figures and include the appropriate units.

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  1. 20 May, 05:05
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    Answer : 63 km/h

    Explanation:

    Outgoing distance = 300 km.

    Outgoing speed = 93 km/h.

    Break time = 1 h

    Return distance = 300 km

    Return speed = 56 km/h

    Outgoing time = outgoing distance / outgoing speed

    Outgoing time = 300 km / 93 km/h = 3.225806451612 h

    Return time = return distance / return speed

    Return time = 300 km / 56 km/h = 5.357142867142 h

    Total distance =. Outgoing distance + return distance travelled

    Total distance = 300 km + 300 km = 600 km

    Total time = outgoing time + break time + return time

    Total time = 3.225806451612 h + 1 h + 5. 357142867142 h = 9.582949308754 h

    Average speed = total distance / total time

    Average speed = 600 km / 9.582949308754 h

    Average speed = 62.61120462042 km/h = 63 km/h
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