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15 October, 13:22

Steam enters an adiabatic turbine at 10 MPa and 500oC and leaves at 10 kPa with a quality of 50.027 percent. Neglecting the changes in kinetic and potential energies, determine the power output in MW using 3 decimals for mass flow rate of 15.469.

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  1. 15 October, 15:23
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    power output = 30730.71 kJ/s

    Explanation:

    given data

    pressure p1 = 10 MPa

    temperature = 500° C

    pressure p2 = 10 kPa

    quality = 50.027 % = 0.50027

    mass flow rate m = 15.469

    to find out

    power output in MW

    solution

    we know energy balance equation here that is

    Energy (in) = Energy (out)

    mh1 = P (out) + mh2

    P (out) = - m (h2 - h1) ... 1

    we know here h1 from steam table that is

    h1 = 3375.1 kJ/kg and

    hf = 191.81 and hfg = 2392.1 kJ/kg

    h2 = hf + quality hfg

    h2 = 191.81 + 0.50027 (2392.1) = 1388.50 kJ/kg

    so from equation 1 we get power output

    P (out) = - m (h2 - h1)

    P (out) = - 15.469 (1388.50 - 3375.1)

    power output = 30730.71 kJ/s
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