Ask Question
11 June, 04:53

Zinc metal reacts with HCl as follows: Zn + 2 HCl ⇒ ZnCl2 + H2 What mass of zinc metal is needed to produce 600.0 mL of hydrogen gas collected over water at 30.0°C and at 775 mmHg?

+1
Answers (1)
  1. 11 June, 06:05
    0
    it is required a mass of Zn equal to m = 1.608 gr of Zn

    Explanation:

    Assuming that the hydrogen behaves as an ideal gas (in reality it has positive deviations from the gas law, but we can neglect the small correction), then

    P*V=n*R*T

    n = P*V / (R*T)

    where

    P = absolute pressure = 775 mmHg = 1.02 atm

    T = absolute temperature = 30°C+273 = 303 K

    V = volume = 600 mL = 0.6 L

    R = ideal gas constant = 0.082 atm*L / (mol*K)

    n = number of moles of H₂ gas

    replacing values

    n = P*V / (R*T) = 1.02 atm*0.6 L / (0.082 atm*L / (mol*K) * 303 K) = 0.0246 moles of H₂

    from the reaction

    Zn + 2 HCl ⇒ ZnCl2 + H2

    since 1 mole of H2 requires 1 mole of Zn to react, then

    m = nz * M

    where

    nz = number of moles of zinc = number of moles of H₂ gas = 0.0246 moles

    M = molecular weight of zinc = 65.38 gr/mol

    m = mass of zinc required

    therefore

    m = 0.0246 moles * 65.38 gr/mol = 1.608 gr of Zn

    m = 1.608 gr of Zn
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Zinc metal reacts with HCl as follows: Zn + 2 HCl ⇒ ZnCl2 + H2 What mass of zinc metal is needed to produce 600.0 mL of hydrogen gas ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers