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1 December, 13:52

Assuming that the density of a person is the same as the density of water, what buoyant force does the atmosphere exert on a person whose mass is 70 kg?

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  1. 1 December, 16:42
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    the buoyant force F will be 0.84 N

    Explanation:

    Assuming that a person has the density of water, then its volume could be calculated through

    V = m/ρ, where m = mass of the person, ρ = density of water

    then

    V = m/ρ = 70 kg / 1000 kg/m³ = 0.07 m³

    then the buoyant force will be equal to the mass of displaced air in the volume V.

    if we assume that the density of air in the atmosphere is ρa=1.225 kg/m³ then the buoyant force F will be

    F = ρa*V*g = 0.07 m³*1.225 kg/m³ * 9.8 m/s² = 0.84 N
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