An electron travels with speed 6.0*10^6 m/s between the two parallel charged plates shown in the figure. The plates are separated by 1.0 cm and are charged by a 200 Volt battery.

What magnetic field strength will allow the electron to pass between the plates without being deflected?

B = 3.33 m T

Explanation:

Given that

Speed, C = 6 x 10⁶ m/s

d = 1 cm = 0.01 m

V = 200 V

The electric field E given as

V = E. d

E=Electric field

d=Distance

V=Voltage

200 = 0.01 x E

E=20000 V/m

The relationship between magnetic and electric field given as

E = C x B

20000 = 6 x 10⁶ x B

B = 3333.333 x 10⁻⁶ T

B = 3.33 x 10⁻³ T

B = 3.33 m T

Therefore the magnetic filed will be 3.33 m T.