Ask Question
4 July, 01:43

A single water molecule were oriented such that its dipole moment (magnitude 6.186 * 10 - 30 Cm is along a z axis. How much torque does an 8500 N/C electric field exert on the dipole if the field lies in x z - plane, 42 ∘ above the x - axis?

+1
Answers (1)
  1. 4 July, 05:03
    0
    Torque=6.261*10^-43Nm

    Explanation:

    Torque is given by:

    Torque=dqEsin (phi)

    Where E is a constant=1.6022*10^-19

    d = distance = 6.186*10^-30cm

    Changing to metres=6.186*10^-28m

    q = the charge=8500NC

    Phi = 42°

    Torque = (6.186*10^-28) * 8500 * (1.6022*10^-19) sin42°

    Torque = 8.425*10^-43 * 0.7431

    Torque = 6.261 * 10^-43
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A single water molecule were oriented such that its dipole moment (magnitude 6.186 * 10 - 30 Cm is along a z axis. How much torque does an ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers