Ted Clubber Lang. A hook in boxing primarily involves horizontal flexion of the shoulder while maintaining a constant angle at the elbow. During this punch, the horizontal flexor muscles of the shoulder contract and shorten at an average speed of 75 cm/s. They move through an arc length of 5 cm during the hook, while the first moves through an arc length of 100 cm. What is the average speed of the first during the hook?

Question

Physics

Leticia Watts

28 January, 05:37

Ted Clubber Lang. A hook in boxing primarily involves horizontal flexion of the shoulder while maintaining a constant angle at the elbow. During this punch, the horizontal flexor muscles of the shoulder contract and shorten at an average speed of 75 cm/s. They move through an arc length of 5 cm during the hook, while the first moves through an arc length of 100 cm. What is the average speed of the first during the hook?

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Answers (1)

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Elena Hayes · Answer 1

15 m/s or 1500 cm/s

Explanation:

Given that

Speed of the shoulder, v (h) = 75 cm/s = 0.75 m/s

Distance moved during the hook, d (h) = 5 cm = 0.05 m

Distance moved by the fist, d (f) = 100 cm = 1 m

Average speed of the fist during the hook, v (f) = ? cm/s = m/s

This can be solved by a very simple relation.

d (f) / d (h) = v (f) / v (h)

v (f) = [d (f) * v (h) ] / d (h)

v (f) = (1 * 0.75) / 0.05

v (f) = 0.75 / 0.05

v (f) = 15 m/s

Therefore, the average speed of the fist during the hook is 15 m/s or 1500 cm/s