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20 April, 19:09

Two samples of water are mixed together.

The first sample has a mass of 0.50 kg and is at 0°C. The second sample has a mass of 1.5 kg and is at 100°C. What is the equilibrium temperature of the water, assume this is a closed system? (Cwater = 4.18 kJ/kg*°C.)

A. 75°C

B. 67°C

C. 33°C

D. 50°C

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Answers (1)
  1. 20 April, 19:26
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    Answer;

    A. 75°C

    Explanation;

    Let the change in temp of cold water be x degrees,

    while that of hot water be 100 - x degrees.

    Heat exchange = mcΔt

    Ice

    Δt = x

    m = 0.50 kg

    c = 4.18 kJ/kg*°C

    Hot water

    Δt = 100 - x

    m = 1.5 kg

    c = 4.18

    But;

    Heat lost = heat gained

    0.50 * c * x = 1.5 * c * (100 - x)

    0.50 * x = 1.5 * (100 - x)

    0.5x = 150 - 1.5x

    0.5x + 1.5x = 150 - 1.5x + 1.5x

    2x = 150

    x = 75° C

    Hence; the equilbrium temperature will be 75° C
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