A potential difference of 3.10 nV is set up across a 2.09 cm length of copper wire that has a radius of 2.32 mm. How much charge drifts through a cross section in 3.05 ms? Assume that the resistivity of copper is 1.69 * 10-8 Ω·m.

drift change = 4.5241 * 10^-7 C

Explanation:

Given data

potential difference = 3.10 nV

length = 2.09 cm

radius = 2.32 mm

to find out

charge drifts through a cross section in 3.05 ms

solution

we will apply here drift change formula that is

drift change = potential difference * π * radius² * time / resistance * length

put all the value and we get drift change

drift change = 3.10 * 10^-9 * π * (0.00232) ² * 3.05 * 10^ (-3) / 1.69*10^ (-8) * 0.0209

drift change = 4.5241 * 10^-7 C