Imagine that an uncharged pith ball is brought into the electrostatic field of a charged rod. The side of the pith ball closest to the negatively charged end of the rod will

A. not experience any induced charge and remain neutral.

B. be given a positive charge produced by the movement of electrons to the other end of the ball.

C. be given a negative charge produced by the movement of electrons from the rod.

D. be given a negative charge produced by the movement of electrons from the other end of the ball.

As per the question the uncharged pith ball is taken towards the electrostatic field of a charged rod.

It is told that the side of the pith ball is closest to the negatively charged end of the rod.

The pith ball was initially neutral. The electrons in the atom were oriented in their respective orbits.

Whenever it is taken towards the negative end of the rod, the electrons present in the ball will not stick to their orbit. Basically the closest electrons will suffer electrostatic repulsive force and will come out their orbits. They will move towards the other end of the pith ball. Hence the closest side of the pith ball will acquire positive charges and other side will be negative.

The bound charges nearest to the charged rod is called induced positive charges and bound negative charges present at the other end are called free bound charges. The induced charges and free charges are equal in amount. Hence the pith ball is neutral.

Hence from above we see that only option B is right.

The correct answere is B.

Explanation: When the negative charge rod is brought close to the uncharged pith ball, the electron on side towards the rod will be repelled by the electrostatic field. This will create an electron deficient site. Hence, this side will be given a positive charge.