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19 July, 22:54

A charged particle moves at 2.5 * 104 m/s at an angle of 25° to a magnetic field that has a field strength of 8.1 * 10-2 T. If the magnetic force is 7.5 * 10-2 N, what is the magnitude of the charge?

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Answers (2)
  1. 19 July, 23:56
    0
    the magnitude of charge=q=8.76 x 10⁻⁵C

    Explanation:

    the magnetic force Fm is given by

    Fm = q V B sinθ

    q = charge

    v = velocity = 2.5 x 10⁴ m/s

    B = magnetic field strength = 8.1 x 10⁻²T

    Fm = magnetic force = 7.5 x 10⁻² N

    θ=25°

    so 7.5 x 10⁻² = q (2.5 x 10⁴) (8.1 x 10⁻²) sin25

    q=8.76 x 10⁻⁵C
  2. 20 July, 01:43
    0
    answer is C on edg
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