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12 January, 15:37

A 60.0kg skier starts from rest at the top of a ski slope of height 62.0. Part A If frictional forces do - 1.06*10 4 of work on her as she descends, how fast is she going at the bottom of the slope?

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  1. 12 January, 17:52
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    v = 29.35 m / s

    Explanation:

    potential energy at the height of 62m

    = m g h, m is mass, g is acceleration due to gravity and h is height

    = 60 x 9.8 x 62

    = 36456 J

    negative work done by friction = - 10600 J

    energy at the bottom = 36456 - 10600 = 25856 J

    This energy will be in the form of kinetic energy. If v be velocity at the bottom

    1/2 m v² = 25856

    1/2 x 60 x v² = 25856

    v = 29.35 m / s
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