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25 March, 14:26

A car is moving at 5.82 m/s when it accelerates 2.35m/s^2 for 3.25s. what is its final velocity?

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Answers (2)
  1. 25 March, 17:02
    0
    The final velocity is 13.5m/s

    Explanation:

    a = (v-u) / t

    2.35 = (v-5.82) / 3.25

    7.6375 = v - 5.82

    v = 7.6375 + 5.82

    v = 13.5 m/s
  2. 25 March, 17:33
    0
    Answer: 13.46 m/s

    Explanation:

    Initial velocity V1 = 5.82 m/s

    acceleration A = 2.35m/s^2

    Time taken T = 3.25s

    Final velocity V2 = ?

    Recall that acceleration is the rate of change of velocity per unit time i. e acceleration = (V2 - V1) / T

    2.35m/s^2 = (V2 - 5.82 m/s) / 3.25s

    cross multiply

    2.35m/s^2 x 3.25s = (V2 - 5.82 m/s)

    7.6375m/s = V2 - 5.82 m/s

    V2 = 7.6375m/s + 5.82m/s

    V2 = 13.46 m/s

    Thus, the car final velocity is 13.46 m/s
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