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8 October, 14:32

A fighter jet is launched from an aircraft carrier with the aid of its own engines and a steam-powered catapult. The thrust of its engines is 2.3 x 10^5 N. In being launched from rest it moves a distance of 87 m and has a kinetic energy of 4.5 x 10^7 J at lift-off. What is the work done on the jet by the catapult?

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  1. 8 October, 17:16
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    2.5 x 10⁷ J

    Explanation:

    F = thrust of the engine = 2.3 x 10⁵ N

    d = distance traveled = 87 m

    Work done by the engine is given as

    W = F d = (2.3 x 10⁵) (87) = 200.1 x 10⁵ J

    W' = Net work done

    W'' = work done by catapult

    KE₀ = initial kinetic energy = 0 J

    KE = final kinetic energy = 4.5 x 10⁷ J

    Net work done is given as

    W' = KE - KE₀

    W' = 4.5 x 10⁷ J

    We know that

    W' = W + W''

    4.5 x 10⁷ = 2.001 x 10⁷ + W''

    W'' = 2.5 x 10⁷ J
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