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20 November, 10:51

A car starts moving from the position of rest with uniform acceleration of 8m/s^calculate the distance travelled by it during 10th minute of its motion.

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  1. 20 November, 13:27
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    We calculate the coordinates at t₁ = 9 min and t₂ = 10 min, since the 10th minute is between t₁ and t₂.

    As it leaves from rest, it means that the initial speed is zero

    t₁=9 min=540 s

    t₂=10 min=600 s

    x₁=at₁²/2=8*540²/2=4*291600=1166400 m

    x₂=at₂²/2=8*600²/2=4*360000=1440000 m

    Δx=x₂-x₁=1440000-1166400=273600 m represents the distance traveled by the car in the 10th minute of travel
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