A 1.00x10^3 crate is being pushed across a level floor at a constant speed by a force

The answer is 0.39 m/s ²

Explanation:

Since the box moves with steady speed,

Friction=force in even direction=260*Cos20=244.3N

Ordinary force=mg+FSinθ=1089N

μN=f

μ=244.3/1089=0.224

N=mg-FSinθ=911.1N

a = (260 Cos20-0.224*911.1) / (1000/9.8) = 0.39m/s²