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5 December, 01:19

In a 1.25-T magnetic field directed vertically upward, a particle having a charge of magnitude 8.50 mC and initially moving northward at 4.75 km>s is deflected toward the east.

(a) What is the sign of the charge of this particle.

(b). Find the magnetic force on the particle.

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  1. 5 December, 04:46
    0
    (a). Since the charge enters the magnetic field and was deflected it carries a + ve charge

    (b). The magnetic force on the particle is given as

    F = Bqv

    Where B = magnetic field in Tesla T

    1.25-T

    q = charge 8.50 mC

    v = average velocity of charge

    4.75 km/s converting to

    m/s we have 4.75*1000 = 4750m/s

    Substituting our given corresponding data we have

    F = 1.25*8.50*10^-3*4750

    F = 50.47N

    The magnetic force on the particle is 50.47N
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