Four elements arbitrarily labelled A, B, C, and D have electronegativities of 3.8, 3.3, 2.8, and 1.3, respectively. Place the compounds AB, AD, BD, and AC in order of increasing covalent character

Question

Physics

Loosetooth

19 February, 19:35

Four elements arbitrarily labelled A, B, C, and D have electronegativities of 3.8, 3.3, 2.8, and 1.3, respectively. Place the compounds AB, AD, BD, and AC in order of increasing covalent character

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Answers (1)

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Myah · Answer 1

Answer: AD < BD < AC< AB

Explanation:-

Electronegativity is defined as the property of an element to attract a shared pair of electron towards itself.

Lower is the electronegativity diffrence, more will be the covalent character. Higher is the electronegativity diffrence, more will be the ionic character.

1. AB: Electronegativity difference = electronegativity of A - electronegativity of B = 3.8-3.3 = 0.5

2. AD: Electronegativity difference = electronegativity of A - electronegativity of D = 3.8-1.3 = 2.5

3. BD: Electronegativity difference = electronegativity of B - electronegativity of D = 3.3-1.3 = 2.0

4. AC: Electronegativity difference = electronegativity of A - electronegativity of C = 3.8-2.8 = 1.0

Thus the order of increasing covalent character is AD < BD < AC< AB.