If one doubles the emfs in a circuit and doubles the resistances in the circuit at the same time, what happens to the currents through the resistors? Assume there are only emfs and resistors in the circuit.

Same

Explanation:

Let R be the resistance of the cell and E be the emf.

Let i be the current in the circuit.

i = E / R ... (1)

Now emf and resistance be doubled.

so, i' = 2E/2R = E/R

So, i' = i (From equation (1)

Current remains same.