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25 June, 11:52

A person kicks a rock horizontally off a cliff with a speed of 35m/s. It takes 12 seconds to hit the ground below (don't forget your units). What is the height of the cliff? What is the final vertical velocity? What is the range?

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  1. 25 June, 13:02
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    take gravity g as 9.81

    height of cliff = ut + 1/2at^2 = 1/2 * (9.81) * 12^2 = 706.32 meters

    What is the final vertical velocity

    v=u+at, final velocity v = 0 + 9.81*12 = 117.72 m/s
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