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14 September, 18:05

A bowling bowl is thrown off the top of a building. Determine distance the ball has fallen after falling for 3.0 s. Remember, the gravitational acceleration (g) is 9.8 m/s2. (Hint: d = ½gt2)

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  1. 14 September, 21:45
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    consider the motion of the bowling ball along the vertical direction after it is thrown off.

    assuming down direction as positive.

    Y = vertical displacement of the bowling ball = distance traveled downward = d

    a = acceleration of the ball = acceleration due to gravity = 9.8 m/s²

    t = time of travel = 3.0 s

    v₀ = initial velocity of the ball along the vertical direction = 0 m/s

    using the equation

    Y = v₀ t + (0.5) a t²

    d = 0 (3.0) + (0.5) (9.8) (3.0) ²

    d = (0.5) (9.8) (9.0)

    d = 44.1 m
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