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20 August, 18:52

A turntable rotates counterclockwise at 76 rpm. A speck of dust on the turntable is at 0.45 rad at t=0. What is the angle of the speck at t = 8.0 s? Your answer should be between 0 and 2Ï rad.

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  1. 20 August, 20:28
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    64.08 rad

    Explanation:

    f = 78 rpm = 76 / 60 rps

    θ = 0.45 rad, t = 8 s

    (θ2 - θ1) / t = ω

    θ2 - θ1 = 2 x 3.14 x 76 x 8 / 60 = 63.63

    Angle turns from initial position = 0.45 + 63.63 = 64.08 rad
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