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12 January, 04:57

To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle with the same mass as an electron but the opposite charge (e). If a positron is accelerated by a constant electric field of magnitude 326 N/C, find the following. (a) Find the acceleration of the positron. m/s2 (b) Find the positron's speed after 8.70 Ã 10-9 s. Assume that the positron started from rest. m/s

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  1. 12 January, 06:25
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    (a) 5.73 * 10¹³ m/s²

    (b) 4.99 * 10⁵ m/s

    Explanation:

    (a) We know that Electrical force is the product of electric charge and electric field:

    F = qE

    We also know that Force is the product of mass and acceleration:

    F = ma

    Therefore, equating both of them:

    ma = qE

    Acceleration, a, will be:

    a = (qE) / m

    Electric charge of a positron = 1.602 * 10^ (-19) C

    Mass of a positron = 9.11 * 10^ (-31) kg

    Acceleration will be:

    a = (1.602 * 10^ (-19)) * 9.11 * 10^ (-31)) / 326

    a = 5.73 * 10¹³ m/s²

    (b) Acceleration is the time rate of change of velocity. It is given as:

    a = v/t

    Velocity, v, will then be:

    v = a * t

    Time, t = 8.7 * 10^ (-9) s

    Therefore, velocity will be:

    v = 5.73 * 10^ (13) * 8.7 * 10^ (-9)

    v = 49.85 * 10⁴ m/s = 4.99 * 10⁵ m/s
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