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27 December, 14:08

Note: Take East as the positive direction. A (n) 81 kg fisherman jumps from a dock into a 136 kg rowboat at rest on the West side of the dock. If the velocity of the fisherman is 3.4 m/s to the West as he leaves the dock, what is the final velocity of the fisherman and the boat? Answer in units of m/s

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  1. 27 December, 18:07
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    The final velocity of the fisherman and the boat = - 1.27 m/s

    Explanation:

    Mass of fisherman, M₁ = 81 kg

    Mas of Rowboat, M₂ = 136 kg

    Initial velocity of the fisherman, v₁ = - 3.4 m/s (Westwards)

    Initial velocity of the rowboat, v₂ = 0 m/s (It is at rest)

    The final velocity of the fisherman and the boat, v = ?

    Using the principle of momentum conservation

    M₁v₁ + M₂v₂ = (M₁ + M₂) v

    - (81*3.4) + (136*0) = (81 + 136) v

    -275.4 = 217v

    v = - 275.4/217

    v = - 1.27 m/s
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