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10 June, 22:06

A rigid tank contains 1 kg of air (ideal gas) at 15 °C and 210 kPa. A paddle wheel supplies work input to the air such that final temperature is 97 "C. The specific heats are Cp 1.005 kJ (kg. K) and C-0.718 kJ / (kg. K). Determine the total work done in kJ:

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  1. 11 June, 01:42
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    -58.876 kJ

    Explanation:

    m = mass of air = 1 kg

    T₁ = Initial temperature = 15°C

    T₂ = Final temperature = 97°C

    Cp = Specific heat at constant pressure = 1.005 kJ/kgk

    Cv = Specific heat at constant volume = 0.718 kJ/kgk

    W = Work done

    Q = Heat = 0 (since it is not mentioned we are considering adiabatic condition)

    ΔU = Change in internal energy

    Q = W+ΔU

    ⇒Q = W+mCvΔT

    ⇒0 = W+mCvΔT

    ⇒W = - mCvΔT

    ⇒Q = - 1*0.718 * (97-15)

    ⇒Q = - 58.716 kJ
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