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8 February, 02:49

0.01 kg of 4.0°C water is heated until its temperature is 37°C. If the specific heat of water is 4186J/kg°C, calculate the amount of heat energy needed to cause this

rise in temperature.

(Round to 2 Decimal Places)

+5
Answers (1)
  1. 8 February, 04:10
    0
    Answer: 1381.38 joules

    Explanation:

    The amount of heat energy (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

    Thus, Q = MCΦ

    Given that:

    Q = ?

    Mass of water = 0.01kg

    C = 4186J/kg°C

    Φ = (Final temperature - Initial temperature)

    = 37°C - 4.0°C = 33.0°C

    Then, Q = MCΦ

    Q = 0.01kg x 4186J/kg°C x 33.0°C

    Q = 1381.38 J

    Thus, 1381.38 Joules of heat energy is needed to cause this rise in temperature.
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