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27 June, 01:46

Future space stations will create an artificial gravity by rotating. Consider a cylindrical space station of 380 m diameter rotating about its axis. Astronauts walk on the inside surface of the space station. What rotation period will provide "normal" gravity? On a space walk on the outside of the space station how much gravity would they experience?

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  1. 27 June, 05:25
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    27.66 s

    Explanation:

    Space station creates artificial gravity by rotational movement about its axis.

    The object inside also move in circular motion creating centrifugal force which creates acceleration in them.

    centrifugal acceleration = ω² R where ω is angular velocity and R is radius of the cylindrical space station.

    R = 380 / 2 = 190 m

    Given

    ω² R = g = 9.8

    ω² = 9.8 / R

    = 9.8 / 190

    = 5.15x 10⁻²

    ω = 2.27 x 10⁻¹

    =.227 rad / s

    2π / T =.227 (T is time period of rotation)

    T = 2π /.227

    = 27.66 s.

    outside of the space station they will experience zero acceleration, because they are rotating around the earth.
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