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10 May, 10:14

We often use a spoon to cool coffee by stirring. Some of the heat is conducted from the coffee to the air by this method, but the spoon itself will cool the coffee a little. If a 12 gram aluminum teaspoon at 22 o C is placed in 175 ml of water (coffee's specific heat is close to water's) at 85 o C, what will the final temperature be? (Other factors, such as heat transfer to the air, may be ignored.)

Question 23 options:

78oC

92oC

84o C

82oC

+5
Answers (1)
  1. 10 May, 10:24
    0
    heat lost by coffee = heat gain by aluminum spoon

    heat lost by coffee = mc (85° C - T)

    175 ml of water = 175 grams

    175 grams = (175 / 1000) kg = 0.175 kg

    heat loss by coffee = 0.175 * 4182 J/Kgk (85 - T) = 731.85 (85-T) = 62207.25 - 731.85 T

    heat gain by aluminum spoon = 0.012kg * 897 J/kgK (T - 22) = 10.764 T - 236.808

    10.764 T - 236.808 = 62207.25 - 731.85 T

    10.764 T + 731.85 T = 62207.25 + 236.808

    T = 84.086 ° C approx 84°C
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