A fisherman has caught a very large, 5.0 kg fish from a dock that is 2.0 m above the water. He is using lightweight fishing line that will break under a tension of 54 N or more. He is eager to get the fish to the dock in the shortest possible time. If the fish is at rest at the water's surface, what's the least amount of time in which the fisherman can raise the fish to the dock without losing it?

Question

Physics

Carlee Jimenez

12 June, 20:48

A fisherman has caught a very large, 5.0 kg fish from a dock that is 2.0 m above the water. He is using lightweight fishing line that will break under a tension of 54 N or more. He is eager to get the fish to the dock in the shortest possible time. If the fish is at rest at the water's surface, what's the least amount of time in which the fisherman can raise the fish to the dock without losing it?

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Answers (1)

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Harper Hebert · Answer 1

The least amount of time in which the fisherman can raise the fish to the dock without losing it is t = 2 seconds.

Explanation:

m = 5 kg

h = 2m

Fmax = 54 N

g = 9.8 m/s²

W = m * g

W = 49 N

F = Fmax - W

F = 5 N

F=m*a

a = F/m

a = 1 m/s²

h = a * t²/2

t = √ (2*h/a)

t = 2 seconds