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7 February, 14:04

An object floats in liquid of density 1.2*10kgm/3 with one quarter of its volume above the liquid surface. Determine the density of the object

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  1. 7 February, 17:36
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    900 kg/m³

    Explanation:

    There are two forces on the object: weight and buoyancy.

    Newton's second law:

    ∑F = ma

    B - W = 0

    B = W

    Weight is mass times gravity:

    W = m₀ g

    Mass is density times volume:

    W = ρ₀ V₀ g

    Buoyancy force is equal to the weight of displaced fluid:

    B = ρ V g

    Therefore:

    ρ V g = ρ₀ V₀ g

    ρ V = ρ₀ V₀

    ρ₀ = ρ V / V₀

    One quarter of the object's volume is above the liquid, which means three quarters of its volume is below the surface.

    Given that V = ¾ V₀ and ρ = 1200 kg/m³:

    ρ₀ = 1200 (3/4)

    ρ₀ = 900 kg/m³
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