Ask Question
24 January, 14:36

A hydraulic lift is made by sealing an ideal fluid inside a container with an input piston of cross-sectional area 0.004 m2, and an output piston of cross-sectional area 1.2 m2. The pistons can slide up or down without friction while keeping the fluid sealed inside. What is the maximum weight that can be lifted when a force of 60 N is applied to the input piston

+5
Answers (1)
  1. 24 January, 17:29
    0
    Maximum weight that can be lifted = 18,000 N

    Explanation:

    Given:

    Cross-sectional area of input (A1) = 0.004 m²

    Cross-sectional area of the output (A2) = 1.2 m ²

    Force (F) = 60 N

    Computation:

    Pressure on input piston (P1) = F / A1

    Assume,

    Maximum weight lifted by piston = W

    Pressure on output piston (P2) = W / A2

    We, know that

    P1 = P2

    [F / A1] = [W / A2]

    [60 / 0.004] = [W / 1.2]

    150,00 = W / 1.2

    Weight = 18,000 N

    Maximum weight that can be lifted = 18,000 N
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A hydraulic lift is made by sealing an ideal fluid inside a container with an input piston of cross-sectional area 0.004 m2, and an output ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers