A rescue plane is flying horizontally at a height of 132 m above the ground. The pilot spots a survivor and releases an emergency kit with a parachute. The kit descends at a constant vertical acceleration of and the initial plane horizontal speed is. Assuming air resistance and wind are negligible, how far away from the survivor will the emergency kit hit the ground?

446 m

301 m

2.64 km

426 m

Question

Physics

Bello

6 August, 09:34

A rescue plane is flying horizontally at a height of 132 m above the ground. The pilot spots a survivor and releases an emergency kit with a parachute. The kit descends at a constant vertical acceleration of and the initial plane horizontal speed is. Assuming air resistance and wind are negligible, how far away from the survivor will the emergency kit hit the ground?

446 m

301 m

2.64 km

426 m

+1

Answers (1)

Know the Answer?

Kenzie Warner · Answer 1

Answer;

= 426 m

Explanation;

Time taken to reach Earth = t

s = ut + ½at²

Vertically initial velocity = u = 0

Therefore;

132 = 0t + ½6.89t²

=132/3.445 = t²

= 38.316 = t²

t = 6.19 s

Range = horizontal distance = speed x time

= 68.9 x 6.19

≈ 426 m

Hence the emergency kit impacts the ground 426 m from the survivor