You leave the doctor's office after your annual checkup and recall that you weighed 688 N in her office. You then get into an elevator that, conveniently, has a scale. Find the magnitude and direction of the elevator's acceleration if the scale readsQ: Find the magnitude of the elevator's acceleration if the scale reads 726 NQ: Find the direction of the elevator's acceleration if the scale reads 726 NQ: Find the magnitude of the elevator's acceleration if the scale reads 598 NQ: Find the direction of the elevator's acceleration if the scale reads 598 N

weight of the person = 688 N

a) reading while in the elevator using the scale was 726 N

since when the elevator is going upward the floor of the elevator and the the scale pushes against the person leading to the person experiences a normal force greater than the weight as a result of the acceleration of the elevator and also

F = ma and W, weight = mg

mass of the body = weight / g = 688 / 9.8 = 70.20 kg

net force on the body = force of normal - weight of the body = 726 - 688 = 38 N

ma = 38 N

70.20 kg * a (acceleration) = 38 N

a = 38 / 70.20 = 0.54 m/s² and the elevator is moving upward

b) net force, ma = force of normal - weight of the body = 598 - 688 = - 90 N

a = - 90 / 70.20 = - 1.282 m/s² and the elevator is coming downward