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1 March, 11:54

A light spring having a force constant of 115 N/m is used to pull a 9.00 kg sled on a horizontal frictionless ice rink. The sled has an acceleration of 2.10 m/s2. Part A By how much does the spring stretch if it pulls on the sled horizontally

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  1. 1 March, 15:05
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    Stretch in the spring = 0.1643 (Approx)

    Explanation:

    Given:

    Mass of the sled (m) = 9 kg

    Acceleration of the sled (a) = 2.10 m/s ²

    Spring constant (k) = 115 N/m

    Computation:

    Tension force in the spring (T) = ma

    Tension force in the spring (T) = 9 * 2.10

    Tension force in the spring (T) = 18.9 N

    Tension force in the spring = Spring constant (k) * Stretch in the spring

    18.9 N = 115 N * Stretch in the spring

    Stretch in the spring = 18.9 / 115

    Stretch in the spring = 0.1643 (Approx)
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