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3 November, 15:57

Compare the kinetic energy of a 20,000-kg truck moving at 110 km/h with that of an 80-kg astronaut in orbit moving at 27,500 km/h.

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  1. 3 November, 19:31
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    for the truck:

    M = mass of the truck = 20000 kg

    V = speed of truck = 110 km/h = 110 (km/h) (1000 m/1 km) (1 h/3600 sec) = 30.6 m/s

    kinetic energy of truck is given as

    KE₁ = (0.5) M V²

    inserting the values

    KE₁ = (0.5) (20000) (30.6) ² = 9363600 J

    for the astronaut:

    m = mass of astronaut = 80 kg

    v = speed of astronaut = 27500 km/h = 27500 (km/h) (1000 m/1 km) (1 h/3600 sec) = 7638.9 m/s

    kinetic energy of astronaut is given as

    KE₂ = (0.5) m v²

    inserting the values

    KE₂ = (0.5) (80) (7638.9) ²

    KE₂ = 2.33 x 10⁹ J

    Ratio of kinetic energy of truck with kinetic energy of astronaut is given as

    KE₁ / KE₂ = (9363600) / (2.33 x 10⁹)

    KE₁ / KE₂ = 0.00402

    kinetic energy of truck is 0.00402 time the kinetic energy of astronaut.
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