The gap between electrodes in a spark plug is 0.060 cm. Producing an electric spark in a gasoline-air mixture requires an electric field of 3.0 * 106 V/m. What minimum potential difference must be supplied by the ignition circuit to start a car?

The minimum potential difference must be supplied by the ignition circuit to start a car is - 1800 V

Explanation:

Given data,

E = 3 * 10 ⁶ Δx=0.06/100

We have to find the minimum potential difference

E = - ΔV/Δx

ΔV = - E * Δx

ΔV = -3 * 10 ⁶. 0.06/100

ΔV=-1800 V

The minimum potential difference must be supplied by the ignition circuit to start a car is - 1800 V