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30 June, 18:59

An 80.0 g sample of a gas was heated from 25 ∘C25 ∘C to 225 ∘C. 225 ∘C. During this process, 346 J of work was done by the system and its internal energy increased by 6085 J. 6085 J. What is the specific heat of the gas?

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  1. 30 June, 22:12
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    402 J / (kg ⁰C)

    Explanation:

    m = mass of the sample = 80.0 g = 0.080 kg

    T₀ = Initial temperature of the sample = 25 ⁰C

    T = Final temperature of the sample = 225 ⁰C

    W = Amount of work done by the system = 346 J

    U = Increase in internal energy = 6085 J

    Q = Amount of heat given to the gas

    Amount of heat is given as

    Q = U + W

    Q = 6085 + 346

    Q = 6431 J

    Heat received by sample is given as

    Q = m c (T - T₀)

    inserting the values

    6431 = (0.080) c (225 - 25)

    c = 402 J / (kg ⁰C)
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