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18 April, 07:57

If the applied force changes to 520 N, what is the acceleration of the block up the ramp? Given mass = 46kg Angle of ramp = 50 degrees from horizontal Coefficient of friction = 0.38 Original Fa = 455.4 a = ?

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  1. 18 April, 11:49
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    The normal force Fn = m g cos 50 = 46 * 9.8 *.643 = 290 N

    The frictional force u Fn =.38 * 290 = 110 N

    The gravitational force along the ramp Fg = m g sin 50 = 345 N

    The net force "up" the ramp is then (520 - 110 - 345) = 64.7 N

    So a = F / m = 64.7 N / 46 kg = 1.41 m/s^2
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