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29 June, 20:56

The runner had an initial vertical velocity of - 0.7 m/s and an initial horizontal velocity of 3.6 m/s. If the forces were applied over a period of 0.2 seconds, what are the runner's final vertical and horizontal velocities?

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  1. 29 June, 22:31
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    1.26m/s; 4.96m/s

    Explanation

    Acceleration is defined as the change I'm velocity of an object with respect to time.

    Mathematically,

    Acceleration (a) = change in velocity (v-u) / time (t)

    Where v is the final velocity

    u is the initial velocity

    From the equation, it can be deduced that;

    v = u+at

    If the runner had an initial vertical velocity of - 0.7 m/s over a period of 0.2seconds, its final velocity;

    v = (-0.7) + 9.81 (0.2) (a=g=9.81m/s²)

    v = - 0.7+1.962

    v = 1.26m/s

    If the runner had an initial horizontal velocity of 3 m/s over a period of 0.2seconds, its final velocity;

    v = 3+9.81 (0.2)

    v = 3+1.962

    v = 4.96m/s
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