Ask Question
5 July, 21:57

A parallel-plate capacitor, made of two circular plates of radius R = 10 cm, is connected in series with a resistor of resistance R = 100 Ω and a battery of emf E = 10 V. What is the maximum value of the magnetic field induced by the displacement current between the plates, at a distance r = 5 cm from the axis of the plates while the capacitor is being charged?

+2
Answers (1)
  1. 5 July, 22:33
    0
    At the time when the capacitor starts charging, current through will be maximum.

    Current in the circuit = 10 / 100 =.1 A.

    This is called displacement current Id =.1 A.

    magnetic field between the plates will be due to this displacement current.

    Magnetic field lines will be circular in shape.

    If B be the magnetic field, we shall apply ampere's circuital law to find magnetic field due to displacement current at a distance of 5 cm from axis.

    ∫ B dl = μ₀ Id

    B x 2π x. 05 = 8.85 x 10⁻¹² x. 1

    B = 2.82 x 10⁻¹² T.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A parallel-plate capacitor, made of two circular plates of radius R = 10 cm, is connected in series with a resistor of resistance R = 100 Ω ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers