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27 March, 21:37

A golfer strikes a stationary golf ball that has a mass of 0.02 kg. The golf ball leaves the club with a speed of 180 m/s. A high-speed camera determines that the club was in contact with the ball for 0.56 x 10-3 s. What was the average force applied by the club to the ball in newtons

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  1. 27 March, 22:23
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    Answer

    The average force applied by the club to the ball in Newtons is 6428.5N

    Explanation:

    Step one:

    Given data

    Mass of golf ball = 0.02kg

    Velocity of the ball = 180m/s

    Time = 0.56*10-³s

    Step two:

    We know that the impulse equation is given by

    P*t=m*v

    Where p = impulse in Newton?

    t=time in seconds

    m = mass in kg

    v = velocity in m/s

    Step three

    To find the average force applied we Substitute our data into the equation we have

    P*0.56*10-³=0.02*180

    P=3.6/0.56*10-³

    P=6428.5N
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